2y^2+14y-60=0

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Solution for 2y^2+14y-60=0 equation:



2y^2+14y-60=0
a = 2; b = 14; c = -60;
Δ = b2-4ac
Δ = 142-4·2·(-60)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-26}{2*2}=\frac{-40}{4} =-10 $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+26}{2*2}=\frac{12}{4} =3 $

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